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Question

Number of electrons present in a negative charge of 8 coulomb is?

A
5×1019
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B
2.5×1019
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C
12.8×1019
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D
1.6×1019
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Solution

The correct option is A 5×1019
Magnitude of charge Q=8 C
Magnitude of one electronic charge e=1.6×1019 C
Let the number of electron present be N.
Thus, number of electrons N=Qe
N=81.6×1019=5×1019 electrons

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