Question

Number of lone pairs of electrons on $X$e atoms $Xe{F}_2,Xe{F}_4$ and $Xe{F}_6$ molecules are respectively.

• A. 3, 2 and 1
• B. 4, 3 and 2
• C. 2, 3 and 1
• D. 3, 2 and 0

Answer 1

The correct option is A 3, 2 and 1

$Xe{F}_2=2+\frac{8-2}{2}=2+3$
$bondpairlonepair$

$Xe{F}_4=4+\frac{8-4}{2}=4+2$
$bondpairlonepair$

$Xe{F}_6=6+\frac{8-6}{2}=6+1$
$bondpairlonepair$

Option A is correct.