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Question

Number of moles of KMnO4 required to oxidise one mole of Fe(C2O4) in acidic medium is

A
06
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B
167
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C
02
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D
04
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Solution

The correct option is B 06
MnO4+8H++5eMn2++4H2O
FeC2O4Fe2++C2O24
Fe2+Fe3++e
C2O242CO2+2e
since one nole of FeC2O4 loses 3 moles of electrons while one mole of KMnO4 accepts five moles of electrons, therefore, number of KMnO4 required lo oxidise one mole of FeC2O4=3/5
=0.6 mole.

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