The correct option is B 0⋅6
MnO−4+8H++5e−⟶Mn2++4H2O
FeC2O4→Fe2++C2O2−4
Fe2+⟶Fe3++e−
C2O2−4⟶2CO2+2e−
since one nole of FeC2O4 loses 3 moles of electrons while one mole of KMnO4 accepts five moles of electrons, therefore, number of KMnO4 required lo oxidise one mole of FeC2O4=3/5
=0.6 mole.