CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Number of solutions of the equation tanx+secx=2cosx lying in the interval [0, 2π] is


Solution

The given equation can be written as 

sinx+1=2cos2x

sinx+1=2(1sin2x)

2sin2x+sinx1=0

sinx=1±1+84=1±34=12 or -1

x=π6,5π6

Note : sinx=1 is not possible because tanx is given in the question

Hence, the number of solutions is 2.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image