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Question

Number of solutions of the equation tanx+secx=2cosx lying in the interval [0,2π] is

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is B 2
tanx+secx=2cosxx=π2,3π2
sinx+1=2cos2xsinx+1=22sin2x2sin2x+sinx1=0
sinx=1,12x=π6,5π6

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