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Question

$$O_2$$ gas at STP contained in a flask was replaced by $$SO_2$$ under the same conditions. The weight of $$SO_2$$ will be:


A
Equal to that of O2
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B
Half that of O2
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C
Twice that of O2
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D
One-fourth of O2
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Solution

The correct option is C Twice that of $$O_2$$
Basics of mole concept,

$$1 \: mol \: of \: O_2 =1 \: mol \: SO_2$$

molar mass of $$O_2 = $$ molar mass of $$SO_2$$

$$32 \: g \: O_2 = 64 \: g \: SO_2$$

Thus, the weight will be doubled.

Hence, the correct option is $$\text{C}$$

Chemistry

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