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Question

Observe the following lists

List-IList-II
(A) Maximum value of xy subject to x+y=7 is1) 72
(B) If l2+m2=1 , then the maximum value of l+m is2) 1
(C) If x+y=12, then the minimum Value of x2+y2 is3) 2
(D) Minimum value x28x+17 is 4) 494
5) 0

A
A - 4, B -3, C -1, D -2.
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B
A - 4, B -3, C -2, D -1.
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C
A - 2, B -3, C -5, D -4.
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D
A - 2, B -3, C -1, D -4.
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Solution

The correct option is B A - 4, B -3, C -1, D -2.

(A) use A.M. & G.M.
x+y2(xy)12
(72)(xy)12
(xy)(72)2
(B) y=l+1l2

dydl=1l1l2

dydl=0 when l=12
So m=12
l=12

l+m=2

(C) s=x2+(12x)2
dsdx=2x2(12x)
dsdx=0 when x=6 y=6
s=36+36=72
(D) f(x)=2x8
f(x)=0 at x=y
f(y)=1


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