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Question

Obtain the inverse of the following matrix using elementary operation:
A=⎡⎢⎣30−1230041⎤⎥⎦

A
3432328129
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B
3432328129
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C
3432328129
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D
3284312329
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Solution

The correct option is A 3284312329
GIven A=301230041

Therefore, A1=1|A|adj(A)

A1=13(30)1(80)3284312329

A1=3284312329

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