Question

Of the isomeric hexanes, the isomers that give the minimum and the maximum number of monochloro derivatives are respectively :

• A. 2,3- dimethylbutane and n - hexane
• B. 3 - methylpentane and 2,3- dimethylbutane
• C. 2,2- dimethylbutane and 2 - methylpentane
• D. 2,3 - dimethylbutane and 2 - methylpentane
• E. 2-methylpentane and 2,2-dimethylbutane

Answer 1

The correct option is D 2,3 - dimethylbutane and 2 - methylpentane

The possible isomers of hexane are (i) (ii) (iii) (iv) Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives For structure (iii), (a) (b) [Only 2 monochloroderivatives (minimum) are possible] For structure (i), (a) (b) (c) (d) [5 monochloroderivatives (maximum) are possible]