Question

On bombarding $U^{235}$ by slow neutron, $200MeV$ energy is released. If the power output of atomic reactor is $1.6MW$, then the rate of fission will be

• A. $5\times {10}^{22}/s$
• B. $5\times {10}^{16}/s$
• C. $8\times {10}^{16}/s$
• D. $20\times {10}^{16}/s$

Answer 1

Answer: (B)

$5\times {10}^{16}/s$

Output power of the reactor $P=1.6MW$

Energy released per fission $E=200MeV$

$\therefore$ $E=200\times 1.6\times {10}^{-19}MJ$

Thus rate of fission $R=\frac{P}{E}$

$\therefore$ $R=\frac{1.6}{200\times 1.6\times {10}^{-19}}=5\times {10}^{16}$ $/s$