On heating a salt with $N a O H$ , smell of $N H_{3}$ is obtained. The salt contains :

N H 4^{+}

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N O_{3}^{-}

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N O_{2}^{-}

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C H_{3} C O O^{-}

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Solution

The correct option is A $N H 4^{+}$
The reaction of $N H_{4} C l$ and $N a O H$ yields $N H_{3}$ .
$N H_{4} C l + N a O H \to N a C l + N H_{3} + H_{2} O$

Option A is correct.

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Similar questions

$10 g$ sample

of gas liquor $(N H_{4}^{+} s a l t)$ is boiled with NaOH and the resulting $N H_{3}$
is passed into $60 m l$ of $0.90$ $N H_{2} S O_{4}$ . Excess $H_{2} S O_{4}$ required

$10 c m^{3}$ of $0.40 N$ $N a O H$ . What is the of $N H_{3}$ in gas liquor ?

Q. The species having

s p^{3}

hybridisation of atomic orbitals of nitrogen is/are

N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}, N F_{3}

are

Q. A sodium salt on treatment with

M g C l_{2}

gives white precipitate only one heating. The anion of the sodium salt is

N H_{3}

can be obtained by

Q. Which of the following salt does not give

N O_{2}

gas on heating?

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On heating a salt with NaOH, smell of NH3 is obtained. The salt contains :

The correct option is A NH4+The reaction of NH4Cl and NaOH yields NH3.NH4Cl+NaOH→NaCl+NH3+H2OOption A is correct.

On heating a salt with $N a O H$ , smell of $N H_{3}$ is obtained. The salt contains :

The correct option is A $N H 4^{+}$
The reaction of $N H_{4} C l$ and $N a O H$ yields $N H_{3}$ .
$N H_{4} C l + N a O H \to N a C l + N H_{3} + H_{2} O$

Option A is correct.