Question

On heating ammonium dichromate and barium azide separately we get:

• A. $N_2$ in both cases
• B. $N_2$ with ammonium dichromate and $NO$ with barium azide
• C. $N_{2}O$ with ammonium dichromate and $N_2$ with barium azide
• D. $N_{2}O$ with ammonium dichromate and $N{O}_2$ with barium azide

Answer 1

The correct option is A $N_2$ in both cases

On heating ammonium dichromate and barium azide separately we get $N_2$ in both cases.

$(N{H}_4{)}_{2}C{r}_2{O}_7\to C{r}_2{O}_3+4H_{2}O+N_2$.

$Ba(N_3{)}_2\to Ba+3N_2$.

Hence option A is correct.