On heating with bleaching powder, ethyl alcohol is converted into:

C H_{3} C O O H

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C H_{3} C H O

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C H_{3} C O C H_{3}

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C H C l_{3}

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Solution

The correct option is C $C H C l_{3}$
Ethyl alcohol reacts with bleaching powder to give chloroform $(C H C l_{3})$ . This reaction is called haloform reaction and occurs in several steps.
$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + C l_{2}$

$H_{2} O + C l_{2} \to H C l + [O]$

$C_{2} H_{5} O H + [O] \to C H_{3} C H O + H_{2} O$

$C H_{3} C H O + C l_{2} \to C C l_{3} C H O$

$2 C C l_{3} C H O + C a (O H)_{2} \to 2 C H C l_{3} + 2 (H C O O) C a$

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