Question

If $3x=2y-2$ is written in the standard form $ax+by+c=0$, what will be the possible values of $a,b$ and $c$?

• A. a = 1, b = -2 and c = 2
• B. a = 3, b = -2 and c = 2
• C. a = -3, b = -2 and c = 1
• D. a = -3, b = 2 and c = -2

Answer 1

Answer: (B), (D)

The correct options are
B

a = 3, b = -2 and c = 2

D

a = -3, b = 2 and c = -2

The given equation is

$3x=2y-2.$

After rearranging the equation, we get

$\Rightarrow 3x-2y+2=0$

On comparing the above equation with $ax+by+c=0$, we get

a = 3, b = -2 and c = 2

$\therefore$ The values of a, b and c are 3, -2 and 2 respectively.

But the equation can also be written as

$(-1)\times (3x-2y+2)=(-1)\times 0$
$\Rightarrow -3x+2y-2=0$

On comparing the above equation with $ax+by+c=0$, we get

a = -3, b = 2 and c = -2

$\therefore$ The values of a, b and c are -3, +2 and -2 respectively.

Hence, we have two sets of values for a, b and c.