On Resolving $a^{6} - b^{6}$ into factors give $(a + b) (a - b) (a^{2} - a b + b^{2}) (a^{2} + a b + b^{2})$ .

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
True

$a^{6} - b^{6} = (a^{3})^{2} - (b^{3})^{2}$

$= (a^{3} + b^{3}) (a^{3} - b^{3})$

$= (a + b) (a^{2} - a b + b^{2}) (a - b) (a^{2} + a b + b^{2})$

Suggest Corrections

Similar questions

$The product (a + b) (a - b) (a^{2} - a b + b^{2}) (a^{2} + a b + b^{2})$ is equal to

a^{6} - b^{6}

Question 84 (ix)

Simplify

$(a - b) (a^{2} + b^{2} + a b) - (a + b) (a^{2} + b^{2} - a b)$

If $A^{2} - B^{2} = x^{2} - \frac{1}{4} a n d A B = \frac{x}{2}$ . Find the value of $A^{6} + B^{6}$ .

Join BYJU'S Learning Program