Question

# On stretching a wire, the elastic energy stored per unit volume is

A
Fl/2AL
B
FA/2L
C
FL/2A
D
FL/2

Solution

## The correct option is A $$Fl/2AL$$Energy stored per unit volume is given as $$\dfrac{1}{2}Stress\times Strain$$=$$\dfrac { 1 }{ 2 } \left[ \dfrac { F }{ A } \right] \left[ \dfrac { l }{ L } \right] =\dfrac { Fl }{ 2AL }$$Physics

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