On throwing a dice once once, the probability of occurrence of an even number is $1 / 2$

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Solution

Even numbers on dice are total $3$ i.e. $2, 4$ and $6$
Probability of occurrance of an even number = $\frac{N o . o f e v e n n u m b e r o n d i c e}{T o t a l n o . o n d i c e} = \frac{3}{6} = \frac{1}{2}$

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