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Question

One card is drawn from a pack of $$ 52 $$ cards, each of the $$ 52 $$ cards being equally likely to be drawn. Find the probability that the cards drawn is 
i. an ace
ii. either red or king
iii. a face card.


Solution

Total cards $$ n(S) = 52 $$

(i) There are four ace cards in pack

$$ n(A) = 4 $$

$$ p(A) = \dfrac{ n(A)}{n(S)} = \dfrac {4 }{52} = \dfrac {1}{13} $$

(ii) There are $$ 26 $$ red cards in a pack and two black king

$$ n(B)  = 26 +2 = 28  $$

$$ P(B) = \dfrac { n(B)}{n(S)} = \dfrac {28}{52} = \dfrac {7}{13} $$

(iii) In a pack of $$ 52 $$ cards : kings queen jacks are called face cards.

$$ P(C) = \dfrac {n(C)}{n(S)} = \dfrac {12}{52} = \dfrac {3}{13} $$



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