One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is either red or king

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Solution

Total cards $n (S) = 52$
There are 26 red cards in a pack and two black kings $n (B) = 26 + 2 = 28$ .
$P (B) = \frac{n (B)}{n (S)} = \frac{28}{52} = \frac{7}{13}$

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One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is either red or king

Total cards n(S)=52There are 26 red cards in a pack and two black kings n(B)=26+2=28. P(B)=n(B)n(S)=2852=713

Total cards $n (S) = 52$
There are 26 red cards in a pack and two black kings $n (B) = 26 + 2 = 28$ .
$P (B) = \frac{n (B)}{n (S)} = \frac{28}{52} = \frac{7}{13}$