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Question

One end of a copper rod of length 1 m and area of cross section 103m2 is immersed in boiling water at 100C and the other end is in ice at 0C. If the coefficient of thermal conductivity of copper is 92 Cal m1s1C1 and the latent heat of ice is 80 Cal g1, then the amount of ice which will melt in one minute is

A
9.2 g
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B
8 g
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C
6.9 g
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D
5.4 g
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Solution

The correct option is C 6.9 g
Heat transferred to ice in time ‘t’ is
Q=(KAΔθl)×t
If ‘m’ is the mass of ice melted, then θ = mL. Therefore,
mL=(KAΔθl)t
m=92×103×1001.0×6080=6.9gm

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