CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

One end of a massless spring of spring constant 100 N/m is fixed at the centre of a frictionless horizontal table and the other end is connected to a body of mass 7 kg lying on the table at rest. The spring has a natural length of 2 m. If the spring remains horizontal and mass is made to rotate at an angular speed of 1 rad/s, then find the elongation in the spring, assuming the elongation to be small compared to the natural length of the spring.


A
14 cm
loader
B
3.5 cm
loader
C
35 cm
loader
D
1.4 cm
loader

Solution

The correct option is A 14 cm
When the body is rotating in a horizontal circular path, then the spring undergoes elongation to provide the required centripetal force for the body.

Applying the equation of circular motion along radial direction
Fnet=mrω2 .....(1)

Now let us assume the extension in spring as x metres.
Spring force Fspring=kx

kx=mrω2 ....(2)

Substituting m= 7 kg, ω= 1 rad/s
r= natural length of spring =2 m in equation (2)

x=mrω2k=7×2×(1)2100=0.14 m= 14 cm

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image