Question

One gram of water at $$80^{0}C$$ is mixed with one gram of ice at $$0^{0}C$$. The resultant temperature is:

A
1000C
B
00C
C
800C
D
400C

Solution

The correct option is D $$0^{0}C$$Let us assume that the complete ice melts and final temperature is T. Then, by principle of calorimetry,$$1(1)(80-T)=1(80)+1(0.5)(T-0)$$$$80-T=80+0.5T$$$$T={ 0 }^{ 0 }C$$Hence, all the ice just melts and final temperature is $${ 0 }^{ 0 }C$$. Physics

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