Question

# One litre of a sample of hard water contains $$55.5$$ mg of $$CaCl_2$$ and $$4.75$$ mg of $$MgCl_2$$. The total hardness in terms of ppm of $$CaCO_3$$ is :

A
5 ppm
B
10 ppm
C
20 ppm
D
none of the above

Solution

## The correct option is B $$10$$ ppm$$55.5$$ g $$CaCl_2\equiv 50$$ g $$CaCO_3$$$$55.5$$ mg $$CaCl_2\equiv 50\times 10^{-3}$$ g $$CaCO_3$$$$47.5$$ g $$MgCl_2\equiv 50$$ g $$CaCO_3$$$$47.5$$ mg $$MgCl_2\equiv 50\times 10^{-3}$$ g $$CaCO_3$$Total $$CaCO_3=(50+50)\times 10^{-3}=10^{-2}$$ g/LHardness in terms of ppm $$=\dfrac {10^{-2}}{1000}\times 10^6$$ mL $$=10$$ ppmChemistry

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