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Question

One mode of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, $${27}^{o}C$$. The work done on the gas will be:


A
300Rln6
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B
300R
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C
300Rln7
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D
300Rln2
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Solution

The correct option is D $$300R \ln { 2 } \quad $$
Work done in isothermal process is given as
$$W = -nRT  \ ln\dfrac{V2}{V_1}$$
$$W = R \times 300 \  ln\dfrac{P_1}{P_2}$$
$$W = -R \times 300 \ ln \dfrac{P}{2P}$$
$$W = 300R \ ln{2}$$

Physics

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