Question

# One mode of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, $${27}^{o}C$$. The work done on the gas will be:

A
300Rln6
B
300R
C
300Rln7
D
300Rln2

Solution

## The correct option is D $$300R \ln { 2 } \quad$$Work done in isothermal process is given as$$W = -nRT \ ln\dfrac{V2}{V_1}$$$$W = R \times 300 \ ln\dfrac{P_1}{P_2}$$$$W = -R \times 300 \ ln \dfrac{P}{2P}$$$$W = 300R \ ln{2}$$Physics

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