CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

One mole each of a monoatomic, diatomic and triatomic gases are mixed, Cp/Cv for the mixture is

A
1.40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.428
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.67
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1.428
As we know
Cv
for monoatomic gas is 3R/2
for diatomic gas is 5R/2
for triatomic gas is 7R/2
so for their mixture
Cv=[32R+52R+62R]3=73
As CpCv=R
Cp=[52R+72R+82R]3=103
CpCv=107=1.428

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Enthalpy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon