CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

One mole of an ideal diatomic gas (Cv=5cal) was transformed from initial 250C and 1L to the state when temperature is 1000C and volume is 10L. For this process, which of the following holds correct? (R = 2 calories/mol/K) (Take calories as unit of energy and kelvin for temp)

A
ΔH=525
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
ΔS=5 ln373298+2ln10
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
ΔE=375
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
ΔG of the process can not be calculated using the given information
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A ΔH=525
B ΔS=5 ln373298+2ln10
C ΔE=375
D ΔG of the process can not be calculated using the given information
The process can be divided into two steps:
(i) Isochoric process in which volume is kept constant at 1L and temperature is raised from 250C (298 K) to 1000C (373K).
(ii) Isothermal process in which the temperature is kept constant at 1000C (373K) and volume is raised from 1L to 10L.
For isothermal process, the entropy change is ΔS=RlnV2V1=2ln101
For isochoric process, the entropy change is ΔS=CVlnT2T1=5ln373298
Hence, the entropy change for the overall process is ΔS=5ln373298+2ln10
Thus, option B is correct.
For the isothermal process, the change in the internal energy is zero. For the isochoric process, the change in internal energy is equal to the heat transferred.
ΔE=Q=CVΔT=5×75=375. This is also equal to the change in the internal energy for the overall process.
Thus, option C is correct.
The expression for the enthalpy change is ΔH=ΔE+(PFVFPIVI)=ΔE+R(TFTI)=375+2(393298)=525.
Thus, option A is correct.
The free energy change for the process cannot be calculated by using the given information as the expression ΔG=ΔH+TΔS is applicable at a given temperature.
Thus, option D is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Spontaneity and Entropy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon