One mole of anhydrous salt AB dissolves in water and liberates 15 J/mol of heat. The value of DH^°(hydration) of AB is -20.5 J/mol. Hence the dissolution of hydrated salt AB.3H2O (S) is 1) 5.5 J/mol 2) -5.5 J/mol 3) -35.5 J/mol 4) 35.5 J/mol

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Q. One mole of anhydrous salt AB dissolves in water and librates

21.0 J {m o l}^{- 1}

of heat. The value of

Δ_{H y d r a t i o n}

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- 29.4 J {m o l}^{- 1}

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M g C l_{2}

dissolve in water and liberates

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dissolves in water and liberates

25 cal/mol

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Calculate the free energy change when 1 mol of NaCl is dissolved in water at 298 K. given:
(i) Lattice energy of NaCl = -778 kJ $m o l^{- 1}$
(ii) Hydration energy of NaCl = -778 kJ $m o l^{- 1}$
(iii) Entropy change at 298 K = 43 J $m o l^{- 1}$

$(Δ H - Δ U)$ for the formation of carbon monoxide ( $C O$ ) from its elements at $298 K$ is ( $R = 8.314 J K^{- 1} m o l^{- 1}$ )

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