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Question

One mole of atoms of an element M absorb 576 kJ energy for the formation of M+ ions. The total amount of energy required for one mole of M atoms to form tripositive ions is 5140 kJ.2nd and 3rdIP values of the metal are in 2 : 3 ratio. Calculate IP2 and IP3 in kJmol1 respectively.

A
1825,2738
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B
2738,1825
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C
1453,2765
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D
2765,1453
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Solution

The correct option is A 1825,2738
MM+Energyabsorbed
=576kJmole1
IP1=576kJmole1
MM+3Energyabsorbed
=5140kJmole1
MM+3Energyabsorbed
=5140576=4564kJmole1
RatioofIP2 & IP3,=2:3
IP2+IP3=4564kJ
IP2=45645×2=1825kJmole1
IP3=45645×3=2738kJmole1.

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