One mole of f...

Question

One mole of fluorine is reacted with two moles of hot and concentrated $K O H$ . The products formed are $K F, H_{2} O$ and $O_{2}$ The molar ratio of $K F, H_{2} O$ and $O_{2}$ , respectively is;

1 : 1 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1 : 0.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : 2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 : 1 : 0.5$
The chemical reaction is
$2 F_{2} + 4 K O H \to 4 K F + O_{2} + 2 H_{2} O$
Therefore, for $1 m o l e$ of $F_{2}$ the molar ratio will be $2 : 1 : 0.5$

Hence the correct answer is option (b).

Suggest Corrections

Similar questions

C r O_{5}

H_{2} S O_{4}

C r_{2} {(S O_{4})}_{3}

H_{2} O

O_{2}

O_{2}

1

C r O_{5}

O_{2}

6.8

N H_{3} + O_{2} \to N O + H_{2} O

C r O_{5}

H_{2} S O_{4}

C r_{2} {(S O_{4})}_{3}

H_{2} O

O_{2}

O_{2}

1

C r O_{5}

32.0

C H_{4}

O_{2}

C O_{2}

H_{2} O

O_{2}

F_{2}

O F_{2}

O_{2}

H_{2} O

N a F