One mole of N2O4(g) at 300 K is kept in a closed container under 1 atomsphere. It is heated to 600K when 20% by mass of N2O4 decomposes to NO2(g). The resultant pressure (in atm) is .
intialMole N2O41⟶2NO20 ,V=1 mole×R×300 K1 atm (i)
at equilibriumMole N2O41−0.2⟶2NO22×0.2 nT=0.8+0.4=1.2Pf×V=nT×R×600 so by substituting volume of (i)