Question

One mole of $N_2{O}_4\left(g\right)$ at 300 K is kept in a closed container under 1 atomsphere. It is heated to 600K when 20% by mass of $N_2{O}_4$ decomposes to $N{O}_2\left(g\right)$. The resultant pressure (in atm) is .

Answer 1

$\underset{Mole}{intial}\underset{1}{N_2{O}_4}⟶\underset{0}{2N{O}_2},V=\frac{1mole\times R\times 300K}{1atm}\left(i\right)$
$\underset{Mole}{atequilibrium}\underset{1-0.2}{N_2{O}_4}⟶\underset{2\times 0.2}{2N{O}_2}{n}_T=0.8+0.4=1.2$$P_f\times V=n_T\times R\times 600$ so by substituting volume of (i)
$P_T=2.4atm$