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Question

One mole of N2H4 loses 10 moles of electrons to form a new compound A. Assuming that all the Nitrogen appears in the new compound. What is the oxidation state of Nitrogen in A?


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Solution

Hydrazine:

  • Hydrazine is a strong base and it is also called Nitrogen hydride.
  • Hydrazine is dangerously unstable.
  • The oxidation state of Hydrogen is +1.
  • The oxidation state of N in Hydrazine N2H4 is x

x+x+1+1+1+1=02x+4=02x=-4x=-42x=-2

  • The oxidation state of N in Hydrazine is -2.
  • Here one mole of Hydrazine contains two moles of N and loses ten electrons.
  • If one N atom loses five electrons, then its oxidation number will increase by 5.
  • Therefore, the oxidation number of N in compound A will be -2+5=3.

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