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Entropy

One mole of w...

Question

One mole of water at $100^{\circ} C$ is converted into steam at $100^{\circ} C$ at a constant pressure of 1 atm. The change in entropy is [heat of vaporisation of water at $100^{\circ} C$ = 540cal/gm ]

A

8.74

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B

18.74

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C

24.06

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D

26.06

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Solution

The correct option is D 26.06
(d) The entropy change = $\frac{h e a t o f v a p o r i s a t i o n}{t e m p e r a t u r e}$

Here, heat of vaporisation = 540cal/ gm $= 540 \times 18 c a l / m o l$

Temperature of water =100+ 273=373K

Therefore, entropy change= $\frac{540 \times 18}{373} = 26.06 c a l / K m o l$

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