One mole of water at 100∘C is converted into steam at 100∘C at a constant pressure of 1 atm. The change in entropy is [heat of vaporisation of water at 100∘C= 540cal/gm ]
A
8.74
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B
18.74
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C
24.06
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D
26.06
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Solution
The correct option is D 26.06
(d) The entropy change =heatofvaporisationtemperature
Here, heat of vaporisation = 540cal/ gm =540×18cal/mol