Question

Question 4
One of the two digits of a two-digit number is three times the other digit. If you inter change the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Answer 1

Let the unit place digit of a two-digit number
bex.Therefore,the tens place digit =3x
$\because$ 2-digit number = 10 $\times$ tens placedigit + unit place digit
$\therefore Originalnumber=10\times 3x+x=30x+x=31x$
According to the question,.
New number + Orginal Number =88
$\Rightarrow 10x+3x+31x=88$
$\Rightarrow 44x=88$
$\Rightarrow x=\frac{88}{44}=2$
Hence,the 2-digit number $=31x=31\times 2=62$