Out of $200$ students $117$ passed in Maths while $96$ passed in Science. $3$ students failed in both the subjects find how many students passed in both the subjects.

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Solution

$M; =$ Mathematics
$S; =$ Science
$n (M \cup S) = n (M) + n (S) - n (M \cap S)$
$\Rightarrow 200 = 117 + 96 - n (M \cap S)$
$\Rightarrow n (M \cap S) = 213 - 200 = 13$
$∴$ $13$ students failed in both Mathematics and Science.

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Out of 200 students 117 passed in Maths while 96 passed in Science. 3 students failed in both the subjects find how many students passed in both the subjects.

M;= MathematicsS;= Sciencen(M∪S)=n(M)+n(S)−n(M∩S)⇒200=117+96−n(M∩S)⇒n(M∩S)=213−200=13∴ 13 students failed in both Mathematics and Science.

Out of $200$ students $117$ passed in Maths while $96$ passed in Science. $3$ students failed in both the subjects find how many students passed in both the subjects.

$M; =$ Mathematics
$S; =$ Science
$n (M \cup S) = n (M) + n (S) - n (M \cap S)$
$\Rightarrow 200 = 117 + 96 - n (M \cap S)$
$\Rightarrow n (M \cap S) = 213 - 200 = 13$
$∴$ $13$ students failed in both Mathematics and Science.