Out of the five integral numbers C is the average of A and D. B is greater than C and less than D. Also B is the average of A and E. The middle most number in the sequence is :
A
A
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B
B
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C
C
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D
D
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Solution
The correct option is B B D−C−A…(1)D>B>C…(2)From(1)and(2)D>B>C>A…(3)AgainE−B−A…(3)butB>A,from(3)So,E>D>B>C>A[SinceBistheaverageofEandAitisequidistantfrombothEandA]