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Question

Out of the following how many have Xe in sp3d hybridization? XeF2,XeF4,XeF6,XeOF2,XeO3 ?

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Solution

Xe has an electronic configuration of 5s25p6
In XeF2, there are two bonding pairs and three lone pairs of electrons. So acc. to VSEPR theory, the structure would be trigonal bypyramidal to avoid electron pair repulsions.(sp3d)
In XeF4, the structure would be square planar. There are four pairs of bonding electrons and two lone pairs in the molecule. The hybridisation would be sp3d2
XeF6 has a pentagonal bipyramidal geometry due to sp3d3 hybridization. One trans position is occupied by a lone pair giving a distorted octahedral shape.
XeOF2 has a trigonal bipyramidal geometry due to sp3d hybridization. Two equatorial positions are occupied by lone pairs of electrons giving a Tshape to molecule.
XeOF4 has a octahedral geometry due to sp3d2 hybridization. One trans position is occupied by a lone pair giving pyramid shape to the molecule.
Thus XeOF2 & XeF2 have sp3d hybridization.

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