Out of the following, the alkene that exhibits optical isomerism is

3-methyl-2-pentene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4-methyl-1-pentene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3-methyl-1-pentene

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2-methyl-2-pentene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 3-methyl-1-pentene
For a compound to show optical isomerism, presence of chiral carbon atom is a necessary condition.

$H_{2} C = H C -^{*} | C H_{3} - C H_{2} - C H_{3}$
3-methyl-1-pentene

Suggest Corrections

Similar questions

Two Isomeric alkenes A and B having molecular formula, $C_{5} H_{9} C l$ on adding $H_{2}$ , A gives optically inactive compound while B gives a chiral compound. The two isomer are

Q. An unknown alkene with formula

C_{7} H_{12}

undergoes oxidation by hot alkaline

K M n O_{4}

to yield, after acidification

6 -

ketoheptanoic acid.

Which of the following is that unknown alkene?

1) Methyl cyclohexene

2) Methyl cyclopentene

3) 2-methyl pentene

Q. 2-Methyl-2- pentene on ozonolysis will give:

3

-methyl-

2

-pentene on reaction with HOCl gives:

Q. 1-Pentene and 3-methyl-1-butene are _______ .

Join BYJU'S Learning Program

Out of the following, the alkene that exhibits optical isomerism is

The correct option is C 3-methyl-1-penteneFor a compound to show optical isomerism, presence of chiral carbon atom is a necessary condition. H2C=HC−H|C∗|CH3−CH2−CH3 3-methyl-1-pentene

The correct option is C 3-methyl-1-pentene
For a compound to show optical isomerism, presence of chiral carbon atom is a necessary condition.

$H_{2} C = H C -^{*} | C H_{3} - C H_{2} - C H_{3}$
3-methyl-1-pentene