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Byju's Answer
Standard XII
Chemistry
Valency and Oxidation State
Oxidation no....
Question
Oxidation no. of
F
e
in
K
3
[
F
e
(
C
N
)
6
]
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Solution
Solution:-
K
3
[
F
e
(
C
N
)
6
]
-
Oxidation number of potassium
(
K
)
=
+
1
Oxidation number of cyanide ion
(
C
N
−
)
=
−
1
Let oxidation number of
F
e
be x.
As we know that sum of oxidation state of ll the atoms in a compound is equal to the overall charge on that compound.
∴
3
(
+
1
)
+
x
+
6
(
−
1
)
=
0
⇒
2
+
x
−
6
=
0
⇒
x
=
6
−
3
⇒
x
=
+
3
Hence the oxidation state of
F
e
in
K
3
[
F
e
(
C
N
)
6
]
is
+
3
.
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