Question

Oxidation no. of $Fe$ in $K_3\left[Fe\right(CN{)}_6]$

Answer 1

Solution:-

$K_3\left[Fe{\left(CN\right)}_6\right]$-

Oxidation number of potassium $\left(K\right)=+1$

Oxidation number of cyanide ion $\left({CN}^{-}\right)=-1$

Let oxidation number of $Fe$ be x.

As we know that sum of oxidation state of ll the atoms in a compound is equal to the overall charge on that compound.

$\therefore 3(+1)+x+6(-1)=0$

$\Rightarrow 2+x-6=0$

$\Rightarrow x=6-3$

$\Rightarrow x=+3$

Hence the oxidation state of $Fe$ in $K_3\left[Fe{\left(CN\right)}_6\right]$ is $+3$.