Oxidation number of $F$ in $H F$ .

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Solution

The correct option is B -1
Oxidation state of $F$ in $H F$ is $- 1.$ As $F$ is the most electronegative element and one electron less to complete its octet.

$H$ has $+ 1$ and $F$ has $- 1$ oxidation state.

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Oxidation number of F in HF.

The correct option is B -1Oxidation state of F in HF is −1. As F is the most electronegative element and one electron less to complete its octet. H has +1 and F has −1 oxidation state.

Oxidation number of $F$ in $H F$ .

The correct option is B -1
Oxidation state of $F$ in $H F$ is $- 1.$ As $F$ is the most electronegative element and one electron less to complete its octet.

$H$ has $+ 1$ and $F$ has $- 1$ oxidation state.