Question

Oxidation number of $N$ in $N_{3}H$ is:

• A. $+1/3$
• B. $-1/3$
• C. $0$
• D. $+3$

Answer 1

The correct option is B $-1/3$

Let oxidation number of '$N$' in $N_{3}H$ be '$x$'

$N_{3}H$ is neutral.

Hence, $3x+1=03x=-1x=\frac{-1}{3}$