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Question

Oxidation number of S in $$SO_4^{2-}$$:


A
3
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B
6
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C
2
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D
-2
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Solution

The correct option is D 6
Let oxidation state of S in $$SO_4^{2-} = x$$
$$\therefore x+ (4 \times - 2) = - 2$$
or $$x - 8 = - 2$$    $$\therefore$$ $$x = +6$$

Chemistry

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