Question

Oxidation state of S in $[HS{O}_4{]}^{-}$ is

• A. +2
• B. +4
• C. +6
• D. -2

Answer 1

The correct option is C

+6

We know,
Generally O. S. (O) = -2
O. S. (H) =+1
Now,
Therefore,
$[HS{O}_4{]}^{-}\Rightarrow 1+n+4(-2)=-4\Rightarrow S=8-2=+6$