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Question

Oxygen molecule is paramagnetic because:


A
no. of bonding electrons > no. of antibonding electrons
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B
no. of bonding electrons < no. of antibonding electrons
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C
no. of bonding electrons = no. of antibonding electrons
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D
presence of unpaired electrons in molecular orbitals.
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Solution

The correct option is B presence of unpaired electrons in molecular orbitals.
Electronic configuration of $$O_2$$:
$$(\sigma 1 s^2) (\sigma * 1 s^2) (\sigma 2 s^2) (\sigma * 2 s^2) (\sigma 2 p_z^2) (\pi 2  p_x^2 = \pi 2 p_y^2) (\pi * 2  p_x^1 = \pi * 2 p_y^1)$$,
 $$(\pi * 2  p_x^1 = \pi * 2 p_y^1)$$ each has one electron or unpaired electron.
So the correct option is $$[D]$$.

Chemistry

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