Question

# Oxygen molecule is paramagnetic because:

A
no. of bonding electrons > no. of antibonding electrons
B
no. of bonding electrons < no. of antibonding electrons
C
no. of bonding electrons = no. of antibonding electrons
D
presence of unpaired electrons in molecular orbitals.

Solution

## The correct option is B presence of unpaired electrons in molecular orbitals.Electronic configuration of $$O_2$$:$$(\sigma 1 s^2) (\sigma * 1 s^2) (\sigma 2 s^2) (\sigma * 2 s^2) (\sigma 2 p_z^2) (\pi 2 p_x^2 = \pi 2 p_y^2) (\pi * 2 p_x^1 = \pi * 2 p_y^1)$$, $$(\pi * 2 p_x^1 = \pi * 2 p_y^1)$$ each has one electron or unpaired electron.So the correct option is $$[D]$$.Chemistry

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