450cm³ of nitrogen monoxide and 200cm³ of oxygen are mixed together and ignited. Calculate the composition of resulting mixture.
2NO+O₂→2NO₂

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Solution

2NO(g) + O2 (g) → 2NO2(g)
2vol : 1 vol → 2vol (By Lussac’s Law)

To calculate amount of unused NO
NO : O2
2 : 1
x : 200
x = 400 cm3
Therefore amount of unused NO = 450-400 = 50 cm3

To calculate amount of NO2 formed
O2 : NO2
1 : 2
200 : x1
x1 = 400 cm3
Therefore amount of NO2 formed = 400 cm3

Unused NO = 50 cm3 NO2 formed = 400 cm3
The composition of total mixture = 450 cm3

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