A bird is sitting in a large closed cage which is placed on a spring balance.It records a wieght of 25N. The bird ( mass m=0.5 kg) flies upward in the cage with an acceleration of 2 m/s^2 .The spring balance will now record a weight of?
(A) 24N
(B)25N
(C)26N
(D)27N

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Solution

w = mg
25 = 0.5g
g = 25/0.5
g=50 m/s²

Now, the bird flies upwards with an acceleration of 2 m/s²

therefore, the new reading on the balance = m $\times$ (g+a)

w_new = 0.5 $\times$ (50+2)
w_new = 26 N

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A bird is sitting in a large closed cage which is placed on a spring balance.It records a wieght of 25N. The bird ( mass m=0.5 kg) flies upward in the cage with an acceleration of 2 m/s^2 .The spring balance will now record a weight of?(A) 24N(B)25N(C)26N(D)27N

w = mg 25 = 0.5g g = 25/0.5 g=50 m/s2 Now, the bird flies upwards with an acceleration of 2 m/s2 therefore, the new reading on the balance = m × (g+a) wnew = 0.5 × (50+2) wnew = 26 N

A bird is sitting in a large closed cage which is placed on a spring balance.It records a wieght of 25N. The bird ( mass m=0.5 kg) flies upward in the cage with an acceleration of 2 m/s^2 .The spring balance will now record a weight of?
(A) 24N
(B)25N
(C)26N
(D)27N

w = mg
25 = 0.5g
g = 25/0.5
g=50 m/s²

Now, the bird flies upwards with an acceleration of 2 m/s²

therefore, the new reading on the balance = m $\times$ (g+a)

w_new = 0.5 $\times$ (50+2)
w_new = 26 N