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Question

a person strikes a nail with a hammer of mass 500 g moving with a velocity of 10 m/s . the hammer comes to rest in 0.01 s after striking the nail . calculate the force exerted by hammer on nail. and the distance moved by the nail in to the plank.

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Solution

Given,
Mass of hammer, m=500 g=0.5 kg
Initial velocity of hammer, u=10 m/s
Final velocity of hammer, v=0
Duration=0.01 a
Using second law of motion,
F=ma
=(v-u) /t
=0.5 (0-10)/0.01=-500 N
The negative sign shows the force of 500 N acts in the opposite direction of motion.
Thus, force exerted by hammer on nail=500 N
Again,
v2-u2=2as0-100=2×(0-10)0.01×ss=100×0.012×10=0.05 m

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