a piece of copper has a cavity inside it.
It's weight in air is 264g and it's weight in water is 220g.
If the density of copper is 8.8 g/cc , what is the volume of the cavity?

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Solution

Volume of a piece of copper with cavity = V
weight in air,M = 264g
weight in water M' = 220g
density of copper, d =8.8 g/cc
Apply Archemede's principle,
Loss of weight of copper piece = weight of water displaced
=> (264-220)*g = d'Vg
Here, d' = density of water = 1g/cc
=> So, V = 44cc = volume of displaced water = volume of the copper piece with cavity.
If there is no cavity in a piece of copper then its volume,V' = M/d = 264/8.8 = 30 cc
So, volume of the cavity = V- V' = 44-30 = 14 cc.

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