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Question

a sugar syrup of weight 214.2 g contains 34.2 g sugar ( C12 H22 O11 ) . calculate mole fraction of sugar in syrup.

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Solution

Mass of syrup = 214.2 g
Mass of sugar =34.2 g

Molar mass of sugar = 342 g/ mol

No. of moles of sugar (nA) =34.2/342 = 0.1 mole

Mass of water in sugar syrup = 214.2-34.2 = 180 g

​No. of moles of water(nB) = 180/18 =10 moles

Mole fraction of sugar (xA) = nA/ (nA + nB) =0.1/ (0.1 +10) =0.1 /10.1 =0.0099


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