CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An A.P. consists of 50terms of which 3rd term is 12 and the last term is 106.Find the 29th term

Open in App
Solution

Given that,

a3 = 12

a50 =106

We know that,

an= a + (n − 1) d

a3 =a + (3 − 1) d

12 = a +2d (I)

Similarly, a50= a + (50 − 1) d

106 = a +49d (II)

On subtracting (I) from(II), we obtain

94 = 47d

d = 2

From equation (I), weobtain

12 = a + 2 (2)

a = 12 − 4= 8

a29 =a + (29 − 1) d

a29 =8 + (28)2

a29 =8 + 56 = 64

Therefore, 29thterm is 64.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conversion of statements to linear equation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon