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Question

ā€˜pā€™ and ā€˜qā€™ are the zeroes of the polynomial
ax2+bx+c. The values of a and b are


A
-1, -(p + q)
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B
1, p + q
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C
1, -(p+q)
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D
-1, -(p+q)
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Solution

The correct option is C 1, -(p+q)

Since, ‘p’ and ‘q’ are the zeroes of the polynomial ax2+bx+c,

(x-p) and (x-q) are the factors of the expression ax2+bx+c,

so ax2+bx+c=(xp)(xq)

ax2+bx+c=x2(p+q)x+pq

By comparing the co-efficients of x2, x, and the constant term, we get

a=1, b=(p+q) and c=pq


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